Current Question
In a large, randomly mating population under Hardy–Weinberg equilibrium, 9% of individuals display a recessive trait. What percentage are heterozygous carriers?
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A.
18%
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B.
42%
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C.
9%
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D.
81%
Correct Answer: B
Explanation:
If q²=0.09, then q=0.30 and p=0.70. Heterozygous frequency = 2pq = 2(0.70)(0.30) = 0.42 or 42%.